Integrand size = 36, antiderivative size = 97 \[ \int x^3 \left (a+b x^3\right ) \left (c+d x+e x^2+f x^3+g x^4+h x^5\right ) \, dx=\frac {1}{4} a c x^4+\frac {1}{5} a d x^5+\frac {1}{6} a e x^6+\frac {1}{7} (b c+a f) x^7+\frac {1}{8} (b d+a g) x^8+\frac {1}{9} (b e+a h) x^9+\frac {1}{10} b f x^{10}+\frac {1}{11} b g x^{11}+\frac {1}{12} b h x^{12} \]
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Time = 0.07 (sec) , antiderivative size = 97, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.028, Rules used = {1834} \[ \int x^3 \left (a+b x^3\right ) \left (c+d x+e x^2+f x^3+g x^4+h x^5\right ) \, dx=\frac {1}{7} x^7 (a f+b c)+\frac {1}{8} x^8 (a g+b d)+\frac {1}{9} x^9 (a h+b e)+\frac {1}{4} a c x^4+\frac {1}{5} a d x^5+\frac {1}{6} a e x^6+\frac {1}{10} b f x^{10}+\frac {1}{11} b g x^{11}+\frac {1}{12} b h x^{12} \]
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Rule 1834
Rubi steps \begin{align*} \text {integral}& = \int \left (a c x^3+a d x^4+a e x^5+(b c+a f) x^6+(b d+a g) x^7+(b e+a h) x^8+b f x^9+b g x^{10}+b h x^{11}\right ) \, dx \\ & = \frac {1}{4} a c x^4+\frac {1}{5} a d x^5+\frac {1}{6} a e x^6+\frac {1}{7} (b c+a f) x^7+\frac {1}{8} (b d+a g) x^8+\frac {1}{9} (b e+a h) x^9+\frac {1}{10} b f x^{10}+\frac {1}{11} b g x^{11}+\frac {1}{12} b h x^{12} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 97, normalized size of antiderivative = 1.00 \[ \int x^3 \left (a+b x^3\right ) \left (c+d x+e x^2+f x^3+g x^4+h x^5\right ) \, dx=\frac {1}{4} a c x^4+\frac {1}{5} a d x^5+\frac {1}{6} a e x^6+\frac {1}{7} (b c+a f) x^7+\frac {1}{8} (b d+a g) x^8+\frac {1}{9} (b e+a h) x^9+\frac {1}{10} b f x^{10}+\frac {1}{11} b g x^{11}+\frac {1}{12} b h x^{12} \]
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Time = 1.16 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.82
method | result | size |
default | \(\frac {a \,x^{4} c}{4}+\frac {a d \,x^{5}}{5}+\frac {a e \,x^{6}}{6}+\frac {\left (a f +b c \right ) x^{7}}{7}+\frac {\left (a g +b d \right ) x^{8}}{8}+\frac {\left (a h +b e \right ) x^{9}}{9}+\frac {b f \,x^{10}}{10}+\frac {b g \,x^{11}}{11}+\frac {b h \,x^{12}}{12}\) | \(80\) |
norman | \(\frac {b h \,x^{12}}{12}+\frac {b g \,x^{11}}{11}+\frac {b f \,x^{10}}{10}+\left (\frac {a h}{9}+\frac {b e}{9}\right ) x^{9}+\left (\frac {a g}{8}+\frac {b d}{8}\right ) x^{8}+\left (\frac {a f}{7}+\frac {b c}{7}\right ) x^{7}+\frac {a e \,x^{6}}{6}+\frac {a d \,x^{5}}{5}+\frac {a \,x^{4} c}{4}\) | \(83\) |
gosper | \(\frac {1}{12} b h \,x^{12}+\frac {1}{11} b g \,x^{11}+\frac {1}{10} b f \,x^{10}+\frac {1}{9} x^{9} a h +\frac {1}{9} x^{9} b e +\frac {1}{8} x^{8} a g +\frac {1}{8} b d \,x^{8}+\frac {1}{7} a f \,x^{7}+\frac {1}{7} b \,x^{7} c +\frac {1}{6} a e \,x^{6}+\frac {1}{5} a d \,x^{5}+\frac {1}{4} a \,x^{4} c\) | \(86\) |
risch | \(\frac {1}{12} b h \,x^{12}+\frac {1}{11} b g \,x^{11}+\frac {1}{10} b f \,x^{10}+\frac {1}{9} x^{9} a h +\frac {1}{9} x^{9} b e +\frac {1}{8} x^{8} a g +\frac {1}{8} b d \,x^{8}+\frac {1}{7} a f \,x^{7}+\frac {1}{7} b \,x^{7} c +\frac {1}{6} a e \,x^{6}+\frac {1}{5} a d \,x^{5}+\frac {1}{4} a \,x^{4} c\) | \(86\) |
parallelrisch | \(\frac {1}{12} b h \,x^{12}+\frac {1}{11} b g \,x^{11}+\frac {1}{10} b f \,x^{10}+\frac {1}{9} x^{9} a h +\frac {1}{9} x^{9} b e +\frac {1}{8} x^{8} a g +\frac {1}{8} b d \,x^{8}+\frac {1}{7} a f \,x^{7}+\frac {1}{7} b \,x^{7} c +\frac {1}{6} a e \,x^{6}+\frac {1}{5} a d \,x^{5}+\frac {1}{4} a \,x^{4} c\) | \(86\) |
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Time = 0.28 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.81 \[ \int x^3 \left (a+b x^3\right ) \left (c+d x+e x^2+f x^3+g x^4+h x^5\right ) \, dx=\frac {1}{12} \, b h x^{12} + \frac {1}{11} \, b g x^{11} + \frac {1}{10} \, b f x^{10} + \frac {1}{9} \, {\left (b e + a h\right )} x^{9} + \frac {1}{8} \, {\left (b d + a g\right )} x^{8} + \frac {1}{6} \, a e x^{6} + \frac {1}{7} \, {\left (b c + a f\right )} x^{7} + \frac {1}{5} \, a d x^{5} + \frac {1}{4} \, a c x^{4} \]
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Time = 0.02 (sec) , antiderivative size = 90, normalized size of antiderivative = 0.93 \[ \int x^3 \left (a+b x^3\right ) \left (c+d x+e x^2+f x^3+g x^4+h x^5\right ) \, dx=\frac {a c x^{4}}{4} + \frac {a d x^{5}}{5} + \frac {a e x^{6}}{6} + \frac {b f x^{10}}{10} + \frac {b g x^{11}}{11} + \frac {b h x^{12}}{12} + x^{9} \left (\frac {a h}{9} + \frac {b e}{9}\right ) + x^{8} \left (\frac {a g}{8} + \frac {b d}{8}\right ) + x^{7} \left (\frac {a f}{7} + \frac {b c}{7}\right ) \]
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Time = 0.24 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.81 \[ \int x^3 \left (a+b x^3\right ) \left (c+d x+e x^2+f x^3+g x^4+h x^5\right ) \, dx=\frac {1}{12} \, b h x^{12} + \frac {1}{11} \, b g x^{11} + \frac {1}{10} \, b f x^{10} + \frac {1}{9} \, {\left (b e + a h\right )} x^{9} + \frac {1}{8} \, {\left (b d + a g\right )} x^{8} + \frac {1}{6} \, a e x^{6} + \frac {1}{7} \, {\left (b c + a f\right )} x^{7} + \frac {1}{5} \, a d x^{5} + \frac {1}{4} \, a c x^{4} \]
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Time = 0.27 (sec) , antiderivative size = 85, normalized size of antiderivative = 0.88 \[ \int x^3 \left (a+b x^3\right ) \left (c+d x+e x^2+f x^3+g x^4+h x^5\right ) \, dx=\frac {1}{12} \, b h x^{12} + \frac {1}{11} \, b g x^{11} + \frac {1}{10} \, b f x^{10} + \frac {1}{9} \, b e x^{9} + \frac {1}{9} \, a h x^{9} + \frac {1}{8} \, b d x^{8} + \frac {1}{8} \, a g x^{8} + \frac {1}{7} \, b c x^{7} + \frac {1}{7} \, a f x^{7} + \frac {1}{6} \, a e x^{6} + \frac {1}{5} \, a d x^{5} + \frac {1}{4} \, a c x^{4} \]
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Time = 0.04 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.85 \[ \int x^3 \left (a+b x^3\right ) \left (c+d x+e x^2+f x^3+g x^4+h x^5\right ) \, dx=\frac {b\,h\,x^{12}}{12}+\frac {b\,g\,x^{11}}{11}+\frac {b\,f\,x^{10}}{10}+\left (\frac {b\,e}{9}+\frac {a\,h}{9}\right )\,x^9+\left (\frac {b\,d}{8}+\frac {a\,g}{8}\right )\,x^8+\left (\frac {b\,c}{7}+\frac {a\,f}{7}\right )\,x^7+\frac {a\,e\,x^6}{6}+\frac {a\,d\,x^5}{5}+\frac {a\,c\,x^4}{4} \]
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